-5x^2+12=2x

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Solution for -5x^2+12=2x equation:



-5x^2+12=2x
We move all terms to the left:
-5x^2+12-(2x)=0
a = -5; b = -2; c = +12;
Δ = b2-4ac
Δ = -22-4·(-5)·12
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{61}}{2*-5}=\frac{2-2\sqrt{61}}{-10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{61}}{2*-5}=\frac{2+2\sqrt{61}}{-10} $

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